Category: fluorescent lamps

Does the power consumption drop when a four-tube fluorescent fixture has either two tubes missing or two tubes that are burned out. If there is a drop in consumption, how significant is it? Is it cost effective to remove two tubes if you don’t need the lumens of four tubes? — M, Connecticut

Most four-tube fluorescent fixtures are effectively two separate two-tube units. They share the same ballast, but otherwise each pair of tubes is independent of the other. Removing one of those pairs from the fixture will save nearly half the energy and expense, and is a good idea if you don’t need the extra illumination.

The two tubes within a pair operate in series: current flowing as a discharge through the gas in one tube also flows through the gas in the other tube. That’s why they both go out simultaneously. Only one of them is actually dead, but since the dead one has lost its ability to sustain a discharge, it can’t pass any current on to its partner. Replacing the dead tube is usually enough to get the pair working again, at least for while.

Leaving dead tubes in a fixture isn’t the same as removing unnecessary tubes. Tubes often die slow, lingering deaths during which they sustain weak or flickering discharges that consume some energy without providing much light. Also, most fluorescent fixtures heat the electrodes at the ends of the tubes to start the discharge. During startup, the ballast runs an electric current through each electrode (hence the two metal contacts at each end of the tube) and the heated electrodes introduces electric charges into the gas so the discharge can start.

That heating current is only necessary during starting, but if the discharge never starts then the ballast may continue to heat the electrodes for days, weeks, or years. If you look at the ends of a tube that fails to start, you may see the electrodes glowing red hot. Because of that heater current, leaving a failed fluorescent tube in a fixture can be waste of energy and money. Be careful removing those tubes from the fixture—although they produce no light, they can still be hot at their ends.

Why do things such as sneakers, T-shirts, and nailpolish change color in the sun? The only explanations I’ve found simple state that the molecules get excited in the sun.

Sunlight consists not only of light across the entire visible spectrum, but of invisible infrared and ultraviolet lights as well. The latter is probably what is causing the color-changing effects you mention.

Ultraviolet light is high-energy light, meaning that whenever it is emitted or absorbed, the amount of energy involved in the process is relatively large. Although light travels through space as waves, it is emitted and absorbed as particles known as photons. The energy in a photon of ultraviolet light is larger than in a photon of visible light and that leads to interesting effects.

First, some molecules can’t tolerate the energy in an ultraviolet photon. When these molecules absorb such an energetic photon, their electrons rearrange so dramatically that the entire molecule changes its structure forever. Among the organic molecules that are most vulnerable to these ultraviolet-light-induced chemical rearrangements are the molecules that are responsible for colors. The same electronic structural characteristics that make these organic molecules colorful also make them fragile and susceptible to ultraviolet damage. As a result, they tend to bleach white in the sun.

Second, some molecules can tolerate high-energy photons by reemitting part of the photon’s energy as new light. Such molecules absorb ultraviolet or other high-energy photons and use that energy to emit blue, green, or even red photons. The leftover energy is converted into thermal energy. These fluorescent molecules are the basis for the “neon” colors that are so popular on swimwear, in colored markers, and on poster boards. When you expose something dyed with fluorescent molecules to sunlight, the dye molecules absorbs the invisible ultraviolet light and then emit brilliant visible light.

What everyday household chemicals (cleaners, paints, detergents, etc.) contain large enough amounts of phosphor to glow under black light?

Fluorescent paints and many laundry detergents contain fluorescent chemicals-chemicals that absorb ultraviolet light and use its energy to produce visible light. Fluorescent paints are designed to do exactly that, so they certainly contain enough “phosphor” for that purpose. Detergents have fluorescent dyes or “brighteners” added because it helps to make fabrics appear whiter. Aging fabric appears yellowish because it absorbs some blue light. To replace the missing blue light, the brighteners absorb invisible ultraviolet and use its energy to emit blue light.

Why does a shave that looks great under incandescent light look terrible under fluorescent light? And, for a woman, what light is best for putting on makeup? — JE

Illumination matters because your skin only reflects light to which it’s exposed. When you step into a room illuminated only by red light your skin appears red, not because it’s truly red but because there is only red light to reflect.

Ordinary incandescent bulbs produce a thermal spectrum of light with a “color temperature” of about 2800° C. A thermal light spectrum is a broad, featureless mixture of colors that peaks at a particular wavelength that’s determined only by the temperature of the object emitting it. Since the bulb’s color temperature is much cooler than that of the sun’s (5800° C), the bulb appears much redder than the sun and emits relatively little blue light. A fluorescent lamp, however, synthesizes its light spectrum from the emissions of various fluorescent phosphors. Its light spectrum is broad but structured and depends on the lamp’s phosphor mixture. The four most important phosphor mixtures are cool white, deluxe cool white, warm white, and deluxe warm white. These mixtures all produce more blue than an incandescent bulb, but the warm white and particularly the deluxe warm white tone down the blue emission to give a richer, warmer glow at the expense of a little energy efficiency. Cool white fluorescents are closer to natural sunlight than either warm white fluorescents or incandescent bulbs.

To answer your question about shaves: without blue light in the illumination, it’s not that easy to distinguish beard from skin. Since incandescent illumination is lacking in blue light, a shave looks good even when it isn’t. But in bright fluorescent lighting, beard and skin appear sharply different and it’s easy to see spots shaving has missed. As for makeup illumination, it’s important to apply makeup in the light in which it will be worn. Blue-poor incandescent lighting downplays blue colors so it’s easy to overapply them. When the lighting then shifts to blue-rich fluorescents, the blue makeup will look heavy handed. Some makeup mirrors provide both kinds of illumination so that these kinds of mistakes can be avoided.

I am interested in experimenting with colored flames, maybe by adding a substance to the flame. Please tell me how to do it and with what kind of substances. — M

You can produce colored flames by adding various metal salts to the burning materials. That’s what’s done in fireworks. These metal salts decompose when heated so that individual metal atoms are present in the hot flame. Thermal energy in the flame then excites those atoms so that their electrons shift among the allowed orbits or “orbitals” and this shifting can lead to the emission of particles of light or “photons”. Since the orbitals themselves vary according to which chemical element is involved, the emitted photons have specific wavelengths and colors that are characteristic of that element.

To obtain a wide variety of colors, you’ll need a wide variety of metal salts. Sodium salts, including common table salt, will give you yellow light—the same light that’s produced by sodium vapor lamps. Potassium salts yield purple, copper and barium salts yield green, strontium salts yield red, and so on. The classic way to produce a colored flame is to dip a platinum wire into a metal salt solution and to hold the wire in the flame. Since platinum is expensive, you can do the same trick with a piece of steel wire. The only problem is that the steel wire will burn eventually.

When an electron hits a neon atom, does it transfer its energy to the atom and lose its own forever?

Most of the collisions between an electron and a neon atom are completely elastic—the electron bounces perfectly from the neon atom and retains essentially all of its kinetic energy. But occasionally the electron induces a structural change in the neon atom and transfers some of its energy to the neon atom. In such a case, the electron rebounds weakly and retains only a fraction of its original kinetic energy. The missing energy is left in the neon atom, which usually releases that energy as light.

Why do only certain orbitals exist in an atom?

Because the electrons in an atom move about as waves, they can follow only certain allowed orbits that we call orbitals. This limitation is equivalent to the case of a violin string—it can only vibrate at certain frequencies. If you try to make a violin string vibrate at the wrong frequency, it won’t do it. That’s because the string vibrates in a wave-like manner and only certain waves fit properly along the strong. Similarly, the electron in an atom “vibrates” in a wave-like manner and only certain waves fit properly around the nucleus.