Tag: falling balls

I don’t understand the relationship between mass, acceleration, and force in New…

Lou Bloomfield Leave a comment

I don’t understand the relationship between mass, acceleration, and force in Newton’s second law.

First off, force causes acceleration. The stronger that force, the more the acceleration. In fact, the two are exactly proportional to one another: double the force and you double the acceleration. Secondly, mass resists acceleration. The more mass an object has, the less it accelerates. The two are exactly inversely proportional to one another: double the mass and you halve the acceleration. These two ideas can be combined into one observation: the force you exert on an object is equal to the product of its mass times the acceleration it experiences. Look at that relationship: if you double the force you exert on an object, you double its acceleration, so that part checks out. If you double the object’s mass and leave the force unchanged, then the acceleration must be halved, so that part checks out. Thus Newton’s second law is simply a sensible relationship between the force you exert on an object, its mass, and its acceleration.

When you pushed the baseball and bowling ball with an equal force, the baseball …

Lou Bloomfield Leave a comment

When you pushed the baseball and bowling ball with an equal force, the baseball went farther on the table because it has a smaller mass. If gravity also exerts an equal force on the 2 balls, like your push, then why do they fall at equal speeds?

The answer is that gravity doesn’t exert equal forces on the 2 balls! It pulls down harder on the bowling ball than it does on the baseball. Suppose the bowling ball has 10 times the mass of the baseball. Then gravity will also exert 10 times the force on the bowling ball that it exerts on the baseball. The result is that the bowling ball is able to keep up with the baseball! The bowling ball may resist acceleration more than the baseball, but the increased gravitational force the bowling ball experience exactly compensates.

If a projectile released or hit at a 45° angle above horizontal should go th…

Lou Bloomfield Leave a comment

If a projectile released or hit at a 45° angle above horizontal should go the farthest, then why, in the game of golf, does the three iron (20° loft) hit a golf ball so much farther in the air than, say, a seven iron (approximately 45° loft) if the same technique and force are produced by the golfer? Is it backspin, shaft length, etc.?

It’s backspin! Air pushes the spinning ball upward and it flies downfield in much the same way as a glider. When you throw a glider for distance, you concentrate your efforts on making it move horizontally because the air will help to keep the glider from hitting the ground too soon. Similarly, the air holds the spinning golf ball up for a remarkably long time so that giving the ball lots of downfield speed is most important for its distance. That’s why a low-loft club like a three iron sends the ball so far.